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-0.85t^2+27.5t-175=0
a = -0.85; b = 27.5; c = -175;
Δ = b2-4ac
Δ = 27.52-4·(-0.85)·(-175)
Δ = 161.25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(27.5)-\sqrt{161.25}}{2*-0.85}=\frac{-27.5-\sqrt{161.25}}{-1.7} $$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(27.5)+\sqrt{161.25}}{2*-0.85}=\frac{-27.5+\sqrt{161.25}}{-1.7} $
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